В прогресии 1) b1=4, q=1/2; 2)b1=1/9, q=3 Найдите b6 и сумму первых шести ее членов

(sin68+cos38)² + (sin38-cos68)²=sin²68 +2sin68cos38 + cos²38 + sin²38 - 2sin38cos68+cos²68=(sin²68 +cos²68) + (sin²38 +cos²38)+2(sin68cos38-sin38cos68)=1+1+2sin(68-38)=2+2sin30=3

5m-2n=3 |-14n=21

4m+7n=11|+14n=22

43m=43

m=1

4*1+7n=11

7n=7

n=7

5m-2n=3     i *4

4m+7n=11   i *(-5)

20m-8n=12

-20m-35n=-55

-43n=-43

n = 1

5m - 2 * 1 = 3

5m - 2 = 3

5m = 3 + 2

5m = 5

m = 5 : 5

m = 1

ответ: (1; 1)