Точка D равноудалена от вершин прямоугольного треугольника ABC(угол ACB=90°). Найдите угол между плоскостями ABC и ACD, если AC=BC=2см, а точка D удалена от плоскости ABC на √3 см.

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bc=10

cos b=5/13

cos b=bc/ab

5/13=10/ab

ab=10*13/5=26

otvet: gipotenuza ab=26cm

v=a*a*a=2*2*2=8см3