Решите прошу ). представьте в виде произведения: а). 2а 2 в 2 – 6ав 3 + 2а 3в ; б). а 2( а – 2 ) – а( а – 2 )2 ; в). 3х – ху – 3у + у 2 ; г). ах – ау + су – сх + х – у .

i'm not sure that's right, but folowing my minds:

as k+k=t and t+t=k it means that t=k. so it doesn't matter what number to substitute for letters, and c=0. hope, i helped you=)

2^2^3=2^6

2^5*2^6=2^11

2^11: 2^9=2^2=4