Решить уравнение : 1/х-4 - 1/ х+6 =5/28

(1 / x - 4 ) - ( 1 / x + 6 ) = 5 / 28  28 * ( x + 6 ) - 28 * ( x - 4 ) = 5 * ( x - 4 ) * ( x + 6 )  x  ≠ 4 ; x  ≠ - 6  28x + 168 - 28x + 112 = 5 * ( x^2 + 6x - 4x - 24 )  280 = 5x^2 + 10x - 120  5x^2 + 10x - 400 = 0  5 * ( x^2 + 2x - 80 ) = 0 d = 4 + 320 = 324 ;   √ d = 18  x1 = ( - 2 + 18 ) : 2 = 8  x2 = ( - 2 - 18 ) : 2 = - 10  ответ 8 и ( - 10 ) 

f(x)=4x-1/x3

f '(x)=x+3/x^4

3х - 9у = 3(х - 3у) ab - bc = b(a - c) 4cx - acx = cx(4 - a) ad + bd + cd = d(a + b + c) abx - acx - adx = ax(b - c - d)