F(x)=4cosx+2. Решите уравнение f’(x)=0

0,125 * 4^(2х-3) = (1/4корня из2)^(-х) 1/8 * (2^2)^(2х-3) = (1/(2^2) * 2^(1/2))^(-х) 2^(-3) * 2^(4х - 6) = (1/(2^2цел 1/2))^(-х) 2^(4х - 9) = (2^(-2,5))^(-х) 2^(4х - 9) = 2^2,5х 4х - 9 = 2,5х 1,5х = 9 х = 6

{х+ху+у=-1,х-ху+у=3

x = -1, y = 2; x = 2, y = -1;