(6-m)²-m(3+m) при m=2/15

34

Объяснение:

(6–m)²–m(3+m)= 36–12m+m²–3m–m²= 36–15m

при m=2/15

36–(15*(2/15))=36–2=34

x=8x-35/x-4             одз: x не= 0

7ч-35/x-4=0

7x^{2}-4x-35=0

d1=4+245=249

x1=(2+\sqrt{249})/7

x2=(2-\sqrt{249})/7