Решить систему уравнений {6x+3=8x-3(2y-4) 2(2y-3y)-4x=2y-8

6x + 3 = 8x - 6y + 12

2x - 6y + 8 = 0

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- 2y - 4x - 2y + 8 = 0

- 4y - 4x + 8 = 0

-x - y - 2 = 0

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2x - 6y + 8 = 0

- x - y - 2 = 0

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x - 7y + 6 = 0

x = 7y - 7

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-2y -4*(7y - 7) - 2y + 8 = 0

- 4y - 28y + 28 + 8 = 0

- 32y = - 36

y = 1.125

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x = 7y - 7 = 7.875 - 7 = 0.875

(m+3)^3-8 = (m+3)^3 - 2^3 = (m+3-+3)²+2(m+3)+4) =

= (m+1)(m²+6m+9+2m+6+4)=(m+1)(m²+8m+19);

(x^2+1)^2-4x^2 = (х²+1-2х)(х²+1+2х)=(х-1)²(х+1)²

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