Разложите многочлен на множители: а) x⁵₋x³-x²-1 б) y³+8+6y²+12y в) n²r⁴+rn²s³-r³sn²-s⁴n² г)a²b⁴c²-a²b²c⁴+a⁴b²c²-a⁴c⁴

А) x⁵₋x³-x²-1= б) y³+8+6y²+12y=(y+2)(y²-2y+4)+6y(y+2)=(y+2)(y²+6y-2y+4)=(y+2)(y²+4y+4)=(y+2)(y+2)²=(y+2)³ в) n²r⁴+rn²s³-r³sn²-s⁴n²=n²((r⁴+rs³³s+s⁴))=n²(r(r³+s³)-s(r³+s³))=n²(r-s)(r+s)(r²-rs+s²) г)a²b⁴c²-a²b²c⁴+a⁴b²c²-a⁴c⁴=a²c²(b⁴-b²c²+a²b²-a²c²)=a²c²(b²(b²-c²)+a²(b²-c²))=a²c²(b²+a²)(b -c)(b+c)

1)   3x+13-8x=33

5x=-20

x=-4

 

2) 6x+12=-7x+25

13x=13

x=1

 

3) x+6(3-3x)=35

x+18-18x=35

17x=-17

x=-1

 

4) 1/3ч+1=-1/4(ч+4/5)

(1+3ч)/3ч=-(ч+0.8)/4

4(1+3ч)=-3(ч+0,8)

4+12ч=-3ч-2,4

15ч=-6,4

]     ч=-32/75

 

i'm not sure that's right, but folowing my minds:

as k+k=t and t+t=k it means that t=k. so it doesn't matter what number to substitute for letters, and c=0. hope, i helped you=)