What elements are generating in the group of addition of the remainders modulo 10?

{1, 3, 5, 7, 9}

Объяснение:

As known, generating element in finite cyclical group   satisfy to the next condition

Also, it is necessary and sufficient conditions for elements in

Therefore, for we get p={1,3,5,7,9}

(-2+ - 5(-2) + 25)) + 2(-2^2+3) = 3^(-4-7+25) +2(-4+3) = 3^(-11+25) + 2(-1) = 3^14+2^(-1) = 42+(-2) = 40

1/(x-3)в квадрате*3x в квадрате