Найдите область определения функции у=12/(√6+х) + √11-х

1)r1=3.8                                              s1=pir^2=pi*3.8^2=14.44pi

2)d=19 r2=19/2=9.5                s2=pi*r^2=pi*9.5^2=90.25pi

отношение -  это частное двух чисел, тогда

90,25pi/14.44pi=6.25

14.44pi/90.25pi=0.16

i'm not sure that's right, but folowing my minds:

as k+k=t and t+t=k it means that t=k. so it doesn't matter what number to substitute for letters, and c=0. hope, i helped you=)