Решите уравнение: 3*3^2x - 7*12^x + 4*4^2x = 0

3*(3^2x) - 7*912^x) + 4*04^2x) = 0 3*(3^2x) - 7*(3^x)*(4^x) + 4*(4^2x) = 0   / (4^2x)3*[(3/4)^2x]   - 7*[(3/4)^x] + 4 = 0(3/4)^x = z 3*(z^2) - 7z + 4 = 0 d = 49 - 4*3*4 = 1 z1 = (7 - 1)/6 z1 = 1 z2 = (7 +1)/6 z2 = 4/3 1)   (3/4)^x = 1 (3/4)^x =  (3/4)^0  x1 = 0 2)  (3/4)^x = 4/3 (3/4)^x =  (3/4)^(-1) x2 = -1

3x+4y=2

4y=2-3x

y=(2-3x)/4

1) x=0.5 y=0.125

2)x=1/3 y=1/4

3)x=0.25 y=0.3125

x/2,5=-6,2/15

15x=-15,5

x=-31/30=- 1 1/30