Решите неравенство (1/36) в степени минус x/3> 6

a+(a+d)+a+2d)=0

a+(a+d)+(a+2d)+(a+3d)=1

3a+3d=0

4a+6d=1

a=(1-6d)/4

3(1-6d)/4+3d=0

6d=3

d=1/2

a=(1-6d)/4=(1-3)/4=-1/2

s=(2a+d(n-1)/2)*n=(2*(-1/2)+(1/2)(10-1))/2*10=17,5

(y²+yx+x²)(y²-yx+x²)(y⁴-y²x²+x⁴)(y⁸-y⁴x⁴+x⁸)=y^16+x^8y^8+y^16

(y²+yx+x²)(y²-yx+x²)=(y^2+x^2)^2-x^2y2=y^4+x^2y^2+y^4,

(y^4+x^2y^2+y^4)(y^4-x^2y^2+y^4)=(x^4+y^4)^2-(x^2y^2)^2=

=y^8+x^4y^4+y^8,

(y^8+x^4y^4+y^8)(y^8-x^4y^4+y^8)=(x^8+y^8)^2-(x^4y^4)^2=

=y^16+x^8y^8+y^16,

ответ: y^16+x^8y^8+y^16