решить
9x⁴-13x²+4=0
(x²-8)²+3(x²-8)=4

Объяснение:

9t² - 13t + 4 = 0

t = 4/9 = x²

t = 1 = x²

x₁ = 1, x₂ = -1, x₃ = 2/3, x₄ = - 2/3

t² + 3t - 4 = 0

t = - 4

t = 1

x² = 4

x² = 9

x₁ = 2, x₂ = -2, x₃ = 3, x₄ = -3

a)14x+21y=7(2x+3y)

b)15a+10b=5(3a+2b)

c)7x-14x=7х(1-2х^2)

(1) 4х = (-1)^n * arcsin(-√2/2) + πn, n€z

4х = (-1)^(n+1) * π/4 + πn, n€z

х = (-1)^(n+1) * π/16 + πn/4, n€z

(2) (x/2-π/8)=π/2+πn, n€z

x/2 = π/8 + π/2+πn, n€z

x/2 = 5π/8+πn, n€z

x = 5π/4+2πn, n€z

(3) 2cos((3x+x)/2)sin((3x-x)/2)=0

cos2x*sinx=0

cos2x=0 или sinx=0 (запись можно в виде совокупности)

1)2х=π/2+πn, n€z

х=π/4+πn/2, n€z

2)х=πk, k€z