Решите уравнение (3х+4)²-(3х-1)(3х+1)=41​

(3х+4)²–(3х–1)(3х+1)=41​;

9x²+24x+16–(9x²–1)=41;

9x²+24x+16–9x²+1=41;

24x= 41–16–1;

24x= 24;

x= 24:24;

x= 1.

ОТВЕТ: 1.

a)х^5+4a^2x^3-4ax^4=x^3(x^2+4a^2-4ax)=x^3(x-2)^2

б)4a^6-12a^5b+9a^4b^2=a^4(4a^2-12ab+9b^2)=a^4(2a-3b)^2