Найдите разность чисел 4 5/14 и 1 8/21​

[tex]4\frac{5}{14}-1\frac{8}{21}=4+\frac{5}{14}-(1+\frac{8}{21})=4+\frac{5}{14}-1-\frac{8}{21}=(4-1)+(\frac{5}{14}-\frac{8}{21}})=3+ \frac{15-16}{42}=3-\frac{1}{42}=2+\frac{42}{42}-\frac{1}{42}=2+\frac{41}{42}=2\frac{41}{42}: \boxed{2\frac{41}{42}}[/tex]

y = (x2 (x3-2x+2))

y = x6-2x3+2x2

y = x4-2(x+1)

y = x4-x+1

x^2-16x+3=0

d=b^2-4ac=244

x1,2=(-b±sqrt(d))/2a

x1=(16+sqrt(244))/2=8+sqrt(61)

x2=(16-sqrt(244))/2=8-sqrt(61)

x1+x2=8+sqrt(61)+8-sqrt(61)=16