Вычислите 1-√3ctg40+1/cos20 40 и 20 в градусах

1-√3*ctq40°+1/cos20° =1 -√3scos40°/sin40° +1/cos20° = ((sin40°-√3cos40°) +2sin20° )/sin40°=(2sin(40° -  60°)+2sin20°   )/sin40°= (2sin(-20°) +2sin20°)/sin40° = (-2sin20° +2sin20°)/sin40° =0/sin40°  =0.  * * *   sin40°-√3cos40° =2((1/2)*sin40°-(√3/2)*cos40°)   =2(cos60°*sin40°-sin60°cos40°)  =2sin(40° -60°) =2sin(-20°) = -2sin20°    * *   *

b1=8

q=1.2

b2=8*1.2=9.6

b3=9.6*1.2=11.52

b4=11.52*1.2=13.824

b5=13.824*1.2=16.5888

s5=b5*q-b1/q-1

s5=16.5888*1.2-8/1.2-1=59.5328