writeln('indexi elementov kotorie bolshe prediduschego: ');
writeln;
for i: =2 to 10 do begin
if a[i]> a[i-1] then write(i,', ');
end;
for i: =2 to 10 do begin
if ((a[i]> =0) and (a[i-1]> =0)) or ((a[i]< 0) and (a[i-1]< 0)) then p: =p+1;
end;
writeln;
if p> 0 then writeln('masiv imeet pari sosednih elementov s odnakovimi znakami') else writeln('masiv ne imeet pari sosednih elementov s odnakovimi znakami');
readln(s);
end.
Ответ дал: Гость
написано для pascal abc
uses graphabc; begin window.title : = 'apple'; var y,y0,x,t: integer; brush.color : = clgreen; y0: =70; x: =70; lockdrawing; for t : = 0 to 8 do begin y: =y0+5*t*t; window.clear(clwhite); circle(x,y,50); redraw; sleep(100); end; end.
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