writeln (' vvedite diametr kruga i storony kvadrata ');
readln (d);
readln (a);
if d< =a then writeln (' krug pomestits9 v kvadrate ')
else writeln (' krug ne pomestits9 v kvadrate ');
readln;
end.
Ответ дал: Гость
вроде бы 100*100=10000 бит=1250 байта
Ответ дал: Гость
program risovalka;
uses crt,graphabc;
var xc,yc,r1,r2,rc,ro,n,i,x,y: integer;
a: real;
begin repeatwrite('ykashi shislo otverstii ot 5 do 10 n=');
read(n);
until n in [5..10];
clrscr; hidecursor;
xc: =windowwidth div 2;
yc: =windowheight div 2;
r1: =40;
r2: =120;
rc: =100; ro: =30;
a: =2*pi/n;
circle(xc,yc,r2);
circle(xc,yc,r1);
for i: =1 to n do begin x: =xc+round(rc*cos(a*i));
y: =yc-round(rc*sin(a*i));
circle(x,y,ro);
end.
Ответ дал: Гость
program rrr; uses crt; const n=9; type massiv=array[1..n]of real; var a: massiv; max,sr: integer; procedure vvod(var x: massiv); var i: integer; beginwriteln('wwedite massiv'); for i: =1 to n doreadln(x[i]); end; procedure vivod(x: massiv); var i: integer; beginfor i: =1 to n dowrite(x[i]: 6: 2,' '); end; procedure sred_ar_i_max(x: massiv,var sr,max: real); var sum: real; i: integer; begins: =0; for i: =1 to n doif x[i]> 0 then s: =s+x[i]; end; sr: =s/n; for i: =1 to n doif (x[i]> 0) and max< x[i] then max: =x[i]; end; vvod(a); clrscr; vivod(a); sred_ar_i_max(a,sr,max); writeln('max=',max: 6: 2,'srednee arifmet=',sr: 6: 2); readln; end.
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