if ((i+1) mod 2=0) and ((i+2) mod 3 =0) and ((i+3) mod 4=0) and ((i+4) mod 5 =0)
then writeln(i);
end.
Ответ дал: Гость
var n: integer;
procedure down(var n: integer); var a: array[1..20] of integer; i, j, s, p: integer; begin i : = 0; while n > 0 do begin i : = i + 1; a[i] : = n mod 10; n : = n div 10; end; p : = i; for i : = 1 to p - 1 do for j : = i + 1 to p do if a[i] < a[j] then begin s : = a[i]; a[i] : = a[j]; a[j] : = s; end; j : = 1; for i : = p downto 1 do begin s : = s + a[i] * j; j : = j * 10; end; n : = s; end;
begin readln(n); down(n); writeln(n); end.
Ответ дал: Гость
varn,i: integer; x0,y0,x1,y1,x2,y2,s: real; begin readln(n); s: =0; readln(x0,y0); x1: =x0; y1: =y0; for i: =2 to n do begin readln(x2,y2); s: =s+sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); x1: =x2; y1: =y2; end; x2: =x0; y2: =y0; s: =s+sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); writeln(s: 10: 2); end.
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