Решить 3.2 со следующим порядком выполнения процессов: 4, 2, 1, 3, 5.

3^i = 18

i = 3

ответ. 3 лампочки.

1)

var

i,k: integer;

a: array [1..14] of integer;

begin

k: =0;

for i: =1 to 14 do

begin

a[i]: =random(46)-15;

write(a[i]: 3);

if a[i] mod 2=0 then k: =i;

end;

if k> 0 then

begin

for i: =k to 13 do a[i]: =a[i]+1;

a[14]: =0;

end;

writeln;

for i: =1 to 14 do write(a[i]: 3);

end.

2)

var

i,k: integer;

a: array [1..14] of integer;

begin

for i: =1 to 14 do

begin

a[i]: =random(46)-15;

write(a[i]: 3);

end;

for i: =1 to 7 do

begin

k: =a[i];

a[i]: =a[i+7];

a[i+7]: =k;

end;

writeln;

for i: =1 to 14 do write(a[i]: 3);

end.

(1 + 2):   3   = 1

1 * 2 + 3 - 4 =1

((1+2) : 3 + 4) : 5 =1

1 * 2 - 3 : (4 +5- 6) =1

1 * 2 + (3 + 4   +5) - (6 + 7) =1

((1 + 2): 3)* (4 + 5 + 6): ( 7+8) =1

type

person=record

fam: string;

imya: string;

day: integer;

end;

var

a: array[1..50] of person;

i,n,z: integer;

begin

write('n='); readln(n);

for i: =1 to n do

begin

write('fam-'); readln(a[i].fam);

write('imya-'); readln(a[i].imya);

write('day-'); readln(a[i].day);

end;

write('z-'); readln(z);

for i: =1 to n do

if a[i].day=z then writeln (a[i].fam, ' ',a[i].imya);

readln;

end.