(2 3/5-1/10х)×20=7решить уравнение

[tex]1)~\displaystyle\tt-\frac{1}{3} +\frac{1}{2}=\frac{-2+3}{6}=\frac{1}{6}; )~\frac{4}{7} +\frac{3}{14} =\frac{8+3}{14} =\frac{11}{14}; )~-2\frac{5}{6} +\big(-\frac{31}{3}\big)=-\frac{17}{6} -\frac{31}{3} =\frac{-17-62}{6}=-\frac{79}{6} =-13\frac{1}{6}; )~7\frac{1}{5} +\big(-4\frac{4}{15}\big)=\frac{36}{5} -\frac{64}{15}=\frac{108-64}{15}=\frac{44}{15} =2\frac{14}{15} ; 5)~2\frac{1}{6}+\big(-\frac{3}{8}\big)=\frac{13}{6}-\frac{3}{8} =\frac{52-9}{24} =\frac{43}{24}= 1\frac{19}{24}; )~-\frac{1}{12}+\frac{7}{60}=\frac{-5+7}{60}=\frac{2}{60} =\frac{1}{30} ; )~-\frac{10}{9}+1\frac{8}{9}=-\frac{10}{9}+\frac{17}{9}=\frac{-10+17}{9}=\frac{7}{9}[/tex]