Найти прозводную. а). у=(5х+sin^2x)*(x^2-cos2x) б). y=(1-2sin^2x)*(1-cos3x)

A)y`=(5+2sinxcosx)(x²-cos2x)+(5x+sin²x)(2x+2sin2x)= =(5+sin2x)(x²-cos2x)+(5x+sin²x)(2x+2sin2x)= =5x²-5cos2x+x²sin2x-sin2xcos2x+10x²+10xsin2x+2xsin²x+2sin²xsin2x= =15x²-5cos2x+x²sin2x-1/2sin4x+10xsin2x+2xsin²x+2sin²xsin2x b)y`=-4sinxcosx(1-cos3x)+3sin3x(1-2sin²x)

1 сарай 3х-2,

2 сарай х+2,

х+2=5/7(3х-2),

1 1/7х=3 3/7,

х=3,

1 сарай 3х-2=3*3-2=7 т,

2 сарай х+2=3+2=5т,

f"(x)=-x^2+x+2

-x^2+x+2=0

d=1+8=9

x1=-1+3=2

x2=-1-3=-4

f(2)=-8/3+2+4-3=1/3

f(-4)=-64/3+8-8-3=-73/3