A10 = 20; d = –1. Знайдіть a1.

a10 = 20

d = –1

аn = a1 + d(n-1)

20 = a1 -(10-1)

a1 -(10-1) = 20

a1 -9 = 20

a1 = 20 + 9

a1 = 29

ответ: 29.

(15а^2-10ab)/(3ab-2b^2)=(5a(3a-2b))/(b(3a-2b))=(5a)/b

a=-2, b=0.1

(5*(-2))/0.1=-100

1)

2(х-1)=3(2х-1)

2x-2=6x-3

1=4x

x=1/4

2)

3(1-x)=4x-11

3-3x=4x-11

14=7x

x=2

3)

3-5(x-1)=x-2

3-5x+5=x-2

10=6x

x=5/3

4)

3(x-2)-2(x-1)=17

3x-6-2x+2=17

x=21