Решить неравенство sqrt(5-4*x- x ²) *( x ²-2*x-3)

5-4x-x^2=

d=4^2-4*5*(-1)=36

x1=(4+sqrt36)/2=5

x2=(4-sqrt36)/2=-1

(x-5)(x+1)

x^2-2*x-3

d=2^2-1*(-3)*4=16

x1=(2+4)/2=3

x2=(-2+4)/2=-1

(x+1)(x-3)

sqrt(x-5)(x-3)(x+1)^2=x+1sqrt(x-5)(x-3)

a6+a8=15

a2*a12=56

a1+5d+a1+7d=15

2a1+12d=15|: 2

a1+6d=7.5

a1=7.5-6d

a2*a12=56

(a1+d)(a1+11d)=56

(7.5-6d+d)(7.5-6d+11d)=56

(7.5-5d)(7.5+5d)=56

7.5^2-(5d)^2=56

56.25-25d^2=56

25d^2=0.25

d^2=0.01

d=0.1

ответ: 0,1

q(x)=2x-5

q(x+3)=2x-5+3=2x-2

q(x+3)=3x

3x=2x-2 => x=-2