Решить систему уравнений x^2-y^2=24 2y-x=-7

2y - x = - 7

x = 2y + 7

x^2 = (2y+7)^2 = 4y^2 + 28y + 49

  x^2 - y^2 = 24

4y^2 + 28y + 49 - y^2 = 24

3y^2 + 28y + 25 = 0

d = 784 - 12*25 = 784 - 300 = 484

v d = 22

y1 = - 28 + 22 \ 6 = - 6\6 = - 1

y2 = - 50\6 = - 25\3 = - 8 1\3 

x = 2y + 7

x1 = - 2 + 7 = 5

x2 = - 50\3 + 21\3 = - 29\3 = - 9 2\3

2х^2-8х-х+4=2х(х--4)=(х-4)(2х-1)

(5,25)^2+4,75(18,9-13,65)=(5,25)^2+4,75*5,25=5,25*(5,25+4,75)=5,25*10=52,5

(^ значит степень)