Решить систему уравнений x^2-y^2=24 2y-x=-7

2y - x = - 7

x = 2y + 7

x^2 = (2y+7)^2 = 4y^2 + 28y + 49

  x^2 - y^2 = 24

4y^2 + 28y + 49 - y^2 = 24

3y^2 + 28y + 25 = 0

d = 784 - 12*25 = 784 - 300 = 484

v d = 22

y1 = - 28 + 22 \ 6 = - 6\6 = - 1

y2 = - 50\6 = - 25\3 = - 8 1\3 

x = 2y + 7

x1 = - 2 + 7 = 5

x2 = - 50\3 + 21\3 = - 29\3 = - 9 2\3

2mx-3m+4x-6=m(2x-3) +2(2m-3)=(m+2)(2x-3)

выйдет -3.3ху