X^2log512(x+7)<=log2(x^2+14x+49)

(-бесконечность;-7] [ -6; + бесконечность)

mawe 10 let. 73-63=10

babywke 55 let. 65-10=55

ole 8 let. 63-55=8

zadanie reshaetsea tak:

babushka+olea=63

babushka+masha=65

babushka+olea+masha=73

olea: 73-63=10

masha: 73-65=8

babushka: 73-10-8=55