Степень окисления ba(oh)2, lio, hbr

sudia po vsemu rech' idet o kolichestve molekul azota. togda obiem raven:

(12*10^20/6*10^23)*22,4=0.0448 litra.

ch3-ch(ch3)-ch2-ch2-ch3

ch2=ch-ch(ch3)-ch2-ch3

  ch-=c-ch(ch3)-ch2-ch3

ch3-c6h5  

h20=2h2+o2

h2+cl2=2hcl

zn+2hcl=zncl2+h2

fe + h₂so₄=feso4+h2

2al + 6hcl = 2alcl3+3h2

2k + 2h₂o =2koh+h2

ba + 2h2o =ba(oh)2+h2