begin for a : = 1000 to 9999 do begin c1 : = a div 1000; c2 : = (a div 100) mod 10; c3 : = (a div 10) mod 10; c4 : = a mod 10; if (c1 < > c2) and (c1 < > c3) and (c1 < > c4) and (c2 < > c3) and (c2 < > c4) and (c3 < > c4) then writeln(a); end; end.
Ответ дал: Гость
varn,i: integer; x0,y0,x1,y1,x2,y2,s: real; begin readln(n); s: =0; readln(x0,y0); x1: =x0; y1: =y0; for i: =2 to n do begin readln(x2,y2); s: =s+sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); x1: =x2; y1: =y2; end; x2: =x0; y2: =y0; s: =s+sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); writeln(s: 10: 2); end.
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