O‘zbekiston xaritasi" iborasida necha bayt axborot bor?

1)

var

a: array [1..5,1..10] of integer;

i,j,p: integer;

begin

for i: =1 to 5 do 

begin

for j: =1 to 10 do

begin

a[i,j]: =random(50)+1;

write(a[i,j]: 3);

end;

writeln;

end;

writeln('меняем 1 и последнюю строки');

for j: =1 to 10 do

begin

p: =a[1,j];

a[1,j]: =a[5,j];

a[5,j]: =p;

end;

for i: =1 to 5 do 

begin

for j: =1 to 10 do

write(a[i,j]: 3);

writeln;

end;

end.

2)

var a: array [1..5, 1..10] of integer; i, j: integer; p: real;

begin for i : = 1 to 5 do begin for j : = 1 to 10 do begin a[i, j] : = random(50) + 1; write(a[i, j]: 3); end; writeln; end; writeln('произведения элементов строк'); for i : = 1 to 5 do begin p : = 1; for j : = 1 to 10 do p : = p * a[i, j]; writeln(p: 25: 0); end; end.

var

a: array[1..100] of integer;

i,n: integer;

begin

readln(n);

writeln('исходный массив');

for i: =1 to n do

begin

a[i]: =random(50)-25;

write(a[i]: 4);

end;

writeln;

writeln('измененный массив');

for i: =1 to n do

begin

if a[i]=0 then a[i]: =n;

if a[i]< 0 then

if (a[i] mod 7=0) then a[i]: =abs(a[i])

else a[i]: =a[i]*(-2);

write(a[i]: 4);

end;

end.

var x: array[1..10] of real; n: integer; begin  for n: =1 to 10 do begin    x[n]: =power(3,n)-5;     writeln(x[n]);     end; end.

вот программа.

var a: array [1..10] of integer;

      i: integer;

begin

  for i: =1 to 10 do begin

  readln(a[i]);

  if a[i]< 0 then a[i]: =abs(a[i]);

  writeln(a[i]);

  end;

end.