program rrr; uses crt; const n=9; type massiv=array[1..n]of real; var a: massiv; max,sr: integer; procedure vvod(var x: massiv); var i: integer; beginwriteln('wwedite massiv'); for i: =1 to n doreadln(x[i]); end; procedure vivod(x: massiv); var i: integer; beginfor i: =1 to n dowrite(x[i]: 6: 2,' '); end; procedure sred_ar_i_max(x: massiv,var sr,max: real); var sum: real; i: integer; begins: =0; for i: =1 to n doif x[i]> 0 then s: =s+x[i]; end; sr: =s/n; for i: =1 to n doif (x[i]> 0) and max< x[i] then max: =x[i]; end; vvod(a); clrscr; vivod(a); sred_ar_i_max(a,sr,max); writeln('max=',max: 6: 2,'srednee arifmet=',sr: 6: 2); readln; end.
Ответ дал: Гость
вот на c:
#include < stdio.h> int main(void){ int i; for(i = 50; i > = -50; i -= 10) { printf("%d\n", i); } printf("\n"); system("pause"); return 0; }
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