Сократите дробь 12с^2-4с÷3с-1

хгрн=100%

1994грн=10%

х=(дробь)100*1994/10=19440грн

х-у=98

х=98+у

х*у=(98+у)у=98у+у^2

(98у+у^2)`=98+2у

98+2у=0

2у=-98

у=-49

х=98+(-49)=49

ответ: 49 и -49

х+у=18.38+0.54=18.92

х-у=18.38-0.54=17.84

ху=18.38*0.54=9.9252

х: у=18.38: 0.54=

(2)/(5)*(5.5m-2)-0.8m < 4.6m-(3)/(4)*(3.6m-1.6)

0,4*(5.5m-2)-0.8m < 4.6m-0,75*(3.6m-1.6)

2,2m-0.8-0.8m< 4.6m-2.7m+1.2

1.4m-0.8< 1.9m+1.2

-0.8-1.2< 1.9m-1.4m

-2< 0.5m

m> -4

m ∈ (-4; + бесконеч)