Осуществите цепочку превращений ch4-c2h2-c2h4-c2h5oh-ch3cho-ch3cooh -ch3coona-ch4

ch4-> c2h2-> c2h4-> c2h5oh-> ch3cho-> ch3cooh-> ch3coona-> ch4

2 ch4=c2h2+3 h2

c2h2+h2=c2h4

c2h4+h2o=c2h5oh

c2h5oh+cuo=cu+ch3cho+h2o

ch3cho+cu(oh)2=ch3cooh+cu2o+h2o

ch3cooh + naoh = ch3coona + h2o

ch3coona + naoh = ch4 + na2co3

массовая доля w=m(na)*100%/m(nacl)=23*100%/58.5=39.3%

м(сnh2n+2) = d*m(h2) = 29*2 = 58 г/моль

м(сnh2n+2) = 12n + 2n + 2 = 14n +2

14n + 2 = 58

14n = 56

n = 56/14

n = 4

формула: с4н10.

бутан - сн3-сн2-сн2-сн3

2-метилпропан

сн3-сн-сн3

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