Составить уравнение реакций ch3coh-ch3ch2oh-ch3ch2br-c2h4-ch3ch 2oh-ch3coh-ch3cooh-ch3coona

Ch3cho+h2 (ni,t) = ch3ch2oh ch3ch2oh+hbr=ch3ch2br+h2o ch3ch2br+koh(сп)=   ch2=ch2   +kbr+h2o c2h4+h2o(h+,t)=c2h5oh ch3ch2oh+cuo(t)=ch3cho+cu+h2o ch3cho+2cu(oh)2=ch3cooh+cu2o+2h2o ch3cooh+naoh=ch3coona+h2o

0.5                       1моль

2naoh+si+h2o=na2sio3+2h2

1                         2моль

 

n(h2)=22.4/22/4=1моль

m(si)=0.5*28=14г

w(si)=14/16*100%=87.5%

2nacl+h2so4=na2so4+2hcl

n(nacl)=58г/58,5г/моль=0,99 моль

n(nacl)=n(hcl)по уравнению реакции

m(hcl)=36,5г/моль*0,99 моль= 36,14г