begin write('n='); readln(n); for i : = 1 to n do begin write('a', i, '='); readln(a[i]); end; f : = 0; writeln; for i : = 1 to n - 1 do if (a[i] mod 2 < > 0) and (a[i + 1] mod 2 = 0) then f : = 1; if f = 0 then begin for i : = 1 to n do if a[i] < 0 then write(a[i]: 4); end else for i : = 1 to n do if a[i] > 0 then write(a[i]: 4); end.
Ответ дал: Гость
может кто перепишет на паскаль
вот на c:
#include < stdio.h> int main(void){ int km, day; day = 1; km = 10; while (km < = 200) { if (km == 20) { printf("20km in %d day\n", day); } km += km / 10; day++; } printf("< 200km in %d day", day); printf("\n"); system("pause"); return 0; }
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