Здравствуйте решить заранее

var a,b,i,s: integer;

begin

writeln('введите 2 числа');

readln(a); readln(b);

s: =0;

if a< b then

for i: =a to b do

  begin

  if i mod 2 = 0 then

  s: =s+1;

  end;

if a> b then

for i: =b to a do

  begin

  if i mod 2 = 0 then

  s: =s+1;

  end;

writeln(s)

end.

3+3-3: 3=5

3-3+3+3=6

3: 3+3+3=7

3*3-3: 3=8

3*3*3: 3=9

3* 3+3: 3 = 10

1)

uses graphabc; begin window.title : = 'circle'; var x,y,r,i: integer; brush.color : = clgreen; y: =20; x: =70; r: =25; for i : = 1 to 7 do circle(x,y+i*60,r); end.

2)

uses graphabc; begin window.title : = 'circle'; var x,y,r,i: integer; brush.color : = clgreen; y: =20; x: =20; r: =30; for i : = 1 to 5 do circle(x+i*70,y+i*70,r); end.

3)

uses graphabc; begin window.title : = 'circle'; var x,y,r,i: integer; brush.color : = clgreen; y: =70; x: =30; r: =60; for i : = 1 to 5 do circle(x+i*60,y,r); end.

var s,a,i: real;

begin

  repeat

      writeln("вес следущего пасажира kg");

      read(a);

      s: =s+a;

      if s< 8000 then

          i: =i+1;

  until s> =8000

  writeln(i);

end.

var b,a,i: real;

begin

  read(a,b);

  repeat

      a: =a+a*0.03;

      i: =i+1;

  until a> =b

  writeln(i);

end.

var i,s: integer;

begin

  for i: = 1900 to 1999 do begin

        s: =s+365;

        if (i mod 400=0) or ((i mod 4 = 0) and (i mod 100< > 0)) then

            s: = s+1;

  end;

  writeln(s);

end.